tag:blogger.com,1999:blog-6912603287930240451.post5939241323170205014..comments2023-08-16T08:02:29.630+00:00Comments on Noncommutative Geometry: A very simple exampleUnknownnoreply@blogger.comBlogger3125tag:blogger.com,1999:blog-6912603287930240451.post-69006180792127911572009-02-21T00:55:00.000+00:002009-02-21T00:55:00.000+00:00Hello, Just two links concerning french research :...Hello, <BR/><BR/>Just two links concerning french research :<BR/><BR/>http://math.univ-lyon1.fr/appel/spip.php?article2<BR/><BR/>http://sciences.blogs.liberation.fr/home/2009/02/les-mathmaticie.htmlAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-6912603287930240451.post-71516235224011729922009-02-02T15:00:00.000+00:002009-02-02T15:00:00.000+00:00i have a question , hope that you can help me ...i...i have a question , hope that you can help me ...<BR/>i'm a M2 stdent of pure math in differential geometry id like to continue my studis in order to get a phd ...anyway there is is prof from clermond ferront who gave us a cours of symbol theories (théorie de symbol) ... it was nice but yet very adanced and unseen ... she gave me the opportunity to continue my PHD with her, and gave me a paper injust someone, a feminin...https://www.blogger.com/profile/00154502799156501513noreply@blogger.comtag:blogger.com,1999:blog-6912603287930240451.post-46685846674604871522009-02-01T08:19:00.000+00:002009-02-01T08:19:00.000+00:00One bad thing about being an amateur student of ma...One bad thing about being an amateur student of math as myself is that you have no access to all the resources. It is still very curious to ask whether there are any algebraic zeros of the Riemann zeta function as I believe their analog for the finite fields are all algebraic. My guess is that these are all transcendental although I do not have the slightest reason why. <BR/><BR/>Best WishesAnonymousnoreply@blogger.com